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4z^2/2z+3=30
We move all terms to the left:
4z^2/2z+3-(30)=0
Domain of the equation: 2z!=0We add all the numbers together, and all the variables
z!=0/2
z!=0
z∈R
4z^2/2z-27=0
We multiply all the terms by the denominator
4z^2-27*2z=0
Wy multiply elements
4z^2-54z=0
a = 4; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·4·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*4}=\frac{0}{8} =0 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*4}=\frac{108}{8} =13+1/2 $
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